The bob of a simple pendulum is displaced from its mean position and then released from rest 0.20 m above its mean position. What is the speed of the bob as it passes through the mean position? (Take g = 10 m/s²)
- A.0 m/s
- B.1 m/s
- C.2 m/s
- D.√10 m/s
Show answer
All the potential energy at the top turns into kinetic energy at the mean position, so v = √(2gh) = √(2 × 10 × 0.20) = 2 m/s. When the bob is released from rest at height h, it has potential energy mgh and no kinetic energy.
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