A pendulum of length L oscillates with an angular amplitude of θ = 60° and time period T. Let T₀ = 2π√(L/g) be the time period for small angle of oscillations, where g is the acceleration due to gravity. If air resistance is negligibly small and the string remains straight, then which one of the following is correct?
- A.T will be slightly greater than T₀.
- B.T will be slightly smaller than T₀.
- C.T will be exactly equal to T₀.
- D.T will depend upon the mass of the bob.
Show answer
The formula T₀ = 2π√(L/g) holds only for small swings; at large amplitudes the period grows.
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