There is a ball of mass 320 g. It has 625 J potential energy when released freely from a height. The speed with which it will hit the ground is
- A.62.5 m/s
- B.2.0 m/s
- C.50 m/s
- D.40 m/s
Correct answer
Explanation
The correct answer is A, 62.5 m/s. In free fall all the potential energy turns into kinetic energy, so 625 J = ½ × 0.32 kg × v², which gives v = 62.5 m/s.
First change the mass into kilograms: 320 g = 0.32 kg. When air resistance is ignored, mechanical energy is conserved, so the kinetic energy just before the ball hits the ground equals the potential energy it started with. Then ½mv² = 625 J, so v² = 2 × 625 ÷ 0.32 = 1250 ÷ 0.32 = 3906.25. The square root of 3906.25 is 62.5, so the ball strikes the ground at 62.5 m/s. As a check, ½ × 0.32 × 62.5 × 62.5 = 625 J.
B is wrong because 2.0 m/s would give a kinetic energy of only 0.64 J.
C is wrong because 50 m/s gives ½ × 0.32 × 2500 = 400 J, not 625 J.
D is wrong because 40 m/s gives 256 J, far less than 625 J.
Exam tip: for a free fall, mgh = ½mv², so v = √(2E/m); always convert grams to kilograms first.
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