In India, the use of diagnostic techniques such as ultrasonography for determining the sex of a foetus is prohibited by which law?
- A.The Medical Termination of Pregnancy Act, 1971
- B.The Pre-conception and Pre-natal Diagnostic Techniques Act, 1994
- C.The Clinical Establishments Act, 2010
- D.The Drugs and Cosmetics Act, 1940
Correct answer
Explanation
The correct answer is B, the Pre-conception and Pre-natal Diagnostic Techniques Act, 1994, commonly called the PCPNDT Act. It regulates the use of pre-natal diagnostic techniques, requires every ultrasound clinic to be registered and to keep records, and prohibits sex selection before or after conception as well as the communication of the sex of the foetus to anyone. It was substantially amended in 2003 to strengthen enforcement.
Option A, the Medical Termination of Pregnancy Act, 1971, lays down the conditions in which a pregnancy may lawfully be terminated and by whom; it is a different statute often confused with this one. Option C, the Clinical Establishments Act, 2010, provides for the registration and minimum standards of clinical establishments generally. Option D, the Drugs and Cosmetics Act, 1940, regulates the manufacture and sale of drugs and cosmetics. The exam point is that the machine is legal and the diagnosis is legal; disclosing the sex of the foetus is the offence.
Read the full article: Medical Diagnostic Technology: X-Ray, CT, MRI and Ultrasound
Practice Questions
View allX-rays were discovered in 1895 by which scientist?
- A.Marie Curie
- B.Wilhelm Conrad Roentgen
- C.Henri Becquerel
- D.Joseph John Thomson
Show answer
Explanation
The correct answer is B, Wilhelm Conrad Roentgen. Working with a discharge tube at the University of Wurzburg in November 1895, Roentgen noticed that a screen coated with a fluorescent salt glowed even when the tube was covered, and he traced the effect to an unknown penetrating radiation that he called X-radiation. For this he received the first Nobel Prize in Physics, awarded in 1901.
Option A, Marie Curie, with Pierre Curie discovered polonium and radium and won Nobel Prizes in Physics in 1903 and in Chemistry in 1911, but her work was on radioactivity and not on X-rays. Option C, Henri Becquerel, discovered natural radioactivity in uranium salts in 1896, a year after Roentgen, and his discovery was in fact prompted by the news about X-rays. Option D, J. J. Thomson, discovered the electron in 1897. Keep the sequence in mind: X-rays in 1895, radioactivity in 1896, the electron in 1897.
Which of the following imaging techniques does not use ionising radiation?
- A.Plain X-ray radiography
- B.Computed tomography
- C.Magnetic resonance imaging
- D.Positron emission tomography
Show answer
Explanation
The correct answer is C, magnetic resonance imaging. MRI works by placing the hydrogen nuclei of the body in a strong static magnetic field and disturbing them with radiofrequency pulses, which lie in the harmless low-energy part of the electromagnetic spectrum. No ionising radiation is involved, which is why MRI can be repeated as often as the physician wishes.
Option A, plain radiography, uses X-rays, which are ionising by definition because they carry enough energy to knock electrons out of atoms. Option B, computed tomography, uses the same X-rays from many angles and delivers a larger dose than a single film. Option D, positron emission tomography, injects a radioactive tracer whose positrons annihilate with electrons to release gamma photons, so it too is ionising. Ultrasound is the other common technique that avoids ionising radiation, which is why ultrasound and MRI are preferred in pregnancy.
The Hounsfield unit, a scale on which water is zero and air is minus one thousand, is used in which imaging technique?
- A.Magnetic resonance imaging
- B.Computed tomography
- C.Ultrasonography
- D.Electrocardiography
Show answer
Explanation
The correct answer is B, computed tomography. The Hounsfield unit, named after Godfrey Hounsfield, expresses how strongly a small volume of tissue attenuates X-rays, on a scale fixed by definition at zero for water and minus one thousand for air. Fat falls below zero, soft tissue a little above it, and dense bone runs to a thousand and beyond, which lets a radiologist judge tissue type from the numbers alone.
Option A is wrong because MRI images are described by signal intensity and sequence weighting, not by a fixed absolute scale. Option C is wrong because ultrasound images are described by echogenicity, with terms such as hyperechoic and anechoic, and the useful measurement is the Doppler velocity of flow. Option D is wrong because electrocardiography records voltages against time in millivolts and produces a trace, not an image. Pair the names in revision: Hounsfield with CT, tesla with MRI, megahertz with ultrasound.
If the potential difference applied to an X-ray tube is doubled while keeping the separation between the filament and the target the same, what will happen to the cutoff wavelength?
- A.It will remain the same
- B.It will be doubled
- C.It will be halved
- D.It will be four times the original wavelength
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Explanation
The correct answer is C, it will be halved. The cutoff or minimum wavelength of the continuous X-ray spectrum arises when an electron gives up its entire kinetic energy in a single collision with the target. Equating the work done by the accelerating voltage with the photon energy gives the relation that the minimum wavelength equals the product of Planck's constant and the speed of light divided by the electronic charge and the voltage. The wavelength is therefore inversely proportional to the applied voltage, so doubling the voltage halves it. This is the Duane-Hunt law.
Option A is wrong because the cutoff depends only on the voltage, which has changed. Option B inverts the relationship and is the commonest error. Option D would follow from an inverse square dependence, which does not apply here. Note also what does not matter: the separation between filament and target and the target material affect intensity and the characteristic lines, not the cutoff wavelength.
Clinical magnetic resonance imaging produces its signal mainly from the nuclei of which element present in the body's water and fat?
- A.Carbon
- B.Hydrogen
- C.Sodium
- D.Phosphorus
Show answer
Explanation
The correct answer is B, hydrogen. A single proton, the nucleus of ordinary hydrogen, has a spin and therefore a magnetic moment, and hydrogen is by far the most abundant such nucleus in the body because the body is largely water and fat. This abundance, combined with a strong magnetic response, is why routine MRI is in effect proton imaging.
Option A, carbon, is abundant in the body but its common isotope carbon-12 has no net nuclear spin and gives no signal; only the rare carbon-13 is magnetically active, and it is used in research spectroscopy. Option C, sodium, and option D, phosphorus, do have magnetically active nuclei, and sodium-23 and phosphorus-31 imaging and spectroscopy exist in specialised research work, but their concentration in tissue is far too low for ordinary clinical scanning. Remember the chain: hydrogen proton, strong static field, radiofrequency pulse, relaxation signal, image.