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GK24
General ScienceMediumAsked in: NDA · NDA-I 2023, GAT

Which among the following is the correct arrangement of halogens in the increasing order of their oxidizing nature ?

  1. A.F, Cl, Br, I
  2. B.Cl, Br, F, I
  3. C.Br, I, Cl, F
  4. D.I, Br, Cl, F

Correct answer

D. I, Br, Cl, F

Explanation

The correct answer is D, I, Br, Cl, F. Oxidising power of the halogens falls as we go down group 17, so iodine is the weakest and fluorine the strongest oxidising agent.

An oxidising agent works by taking electrons. Fluorine is the smallest halogen and the most electronegative element, and its F–F bond is weak, so it grabs electrons more readily than any other element. Going down the group from fluorine to chlorine, bromine and iodine, atoms grow larger and hold an extra electron less firmly, so oxidising power drops. That is why chlorine can push bromine and iodine out of their salts, but iodine cannot displace any of the others.

A is wrong because it is the decreasing order, the exact reverse. B is wrong because it puts fluorine below chlorine and bromine and iodine above it. C is wrong because it places bromine below iodine, while bromine is the stronger oxidiser of the two.

Exam tip: oxidising power F > Cl > Br > I; a higher halogen displaces a lower one from its salt.

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