A metallic sphere of mass 1 kg and volume 2 × 10⁻⁴ m³ is completely immersed in water. The buoyant force exerted by water on the sphere is : (Given : density of water = 1000 kg/m³, g = 10 m/s²)
- A.0.5 N
- B.1.5 N
- C.2 N
- D.2.5 N
Correct answer
Explanation
The correct answer is C, 2 N. By Archimedes' principle, the buoyant force equals the weight of the water displaced by the sphere.
A fully immersed body displaces its own volume of water, here 2 × 10⁻⁴ m³. The mass of that water is density × volume = 1000 × 2 × 10⁻⁴ = 0.2 kg, and its weight is 0.2 × 10 = 2 N. So the upward push is 2 N. The mass of the sphere (1 kg) does not enter the calculation at all; it only decides whether the sphere sinks. Its weight is 10 N, far more than 2 N, so the metal sphere sinks while still feeling a 2 N upthrust.
A, 0.5 N, and B, 1.5 N, are less than the weight of the displaced water. D, 2.5 N, is more than it; none of these matches density × volume × g.
Exam tip: buoyant force = ρ × V × g of the fluid; the body's own mass only decides sinking or floating.
Practice Questions
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