A circular coil of radius R having N number of turns carries a steady current I. The magnetic induction at the centre of the coil is 0.1 tesla. If the number of turns is doubled and the radius is halved, which one of the following will be the correct value for the magnetic induction at the centre of the coil?
- A.0.05 tesla
- B.0.2 tesla
- C.0.4 tesla
- D.0.8 tesla
Show answer
The field at the centre of a coil is proportional to the number of turns and inversely proportional to the radius, so doubling N and halving R makes it four times larger.
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