A boy of mass 52 kg jumps with a horizontal velocity of 2 m/s onto a stationary cart of mass 3 kg. The cart is fixed with frictionless wheels. Which one of the following would be the speed of the cart?
- A.2.15 m/s
- B.1.89 m/s
- C.1.51 m/s
- D.2.51 m/s
Show answer
By the law of conservation of momentum, the boy and the cart move together with the momentum the boy brought, so their speed is 104 ÷ 55, about 1.89 m/s. With frictionless wheels, no outside horizontal force acts, so total momentum stays the same.
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