A ball, thrown vertically upward, rises to a height of 80 m and returns to its original position. The magnitude of its displacement after 7 s of motion will be _______. (take g = 10 m/s2)
- A.35 m
- B.125 m
- C.45 m
- D.25 m
Show answer
Correct answer: A. 35 m
Explanation
The correct answer is A, 35 m. First find the throwing speed from the height: v squared equals u squared minus 2 g h gives u equal to the square root of 2 into 10 into 80, that is 40 metres per second. The ball therefore takes 4 seconds to reach the top, since 40 divided by 10 is 4. Three seconds of the 7 are left for the fall, and in them the ball drops half of 10 into 9, that is 45 metres. Its height above the start is 80 minus 45, which is 35 metres. B is wrong because 125 metres is the total distance covered, 80 up plus 45 down, not the displacement. C is wrong because 45 metres is only the fall in the last 3 seconds. D is wrong because 25 metres matches no step of the working. Exam tip: time up equals time down, so for a ball reaching 80 metres the flight lasts 8 seconds in all.