A force of 20 newton is applied at right angles to a rod at a point 0.5 metre from the axis of rotation. The torque about the axis is
- A.4 newton metre
- B.10 newton metre
- C.40 newton metre
- D.20.5 newton metre
Show answer
Torque is r into F into the sine of the angle between them, and since the force here is perpendicular to the rod the sine is one, so the torque is simply 0.5 multiplied by 20, that is 10 newton metre.
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